A sine function has an amplitude of 3, a period of pi, and a phase shift of pi/2. What is the y-intercept of the function?
A. 3
B.0
C.-3
D. pi/4

Question

A sine function has an amplitude of 3, a period of pi, and a phase shift of pi/2. What is the y-intercept of the function?  A. 3  B.0  C.-3  D. pi/4

Eirian · Answer

Based on the calculations, we can logically deduce that the  y-intercept  of this  sine function  is equal to: A.  3 .       Given the following data:    Amplitude = 3    Period = π    Phase shift = π/2     How to determine the y-intercept of this function?  Mathematically, a  sine function  is modeled by this  equation :  y = Asin(ωt + ø)   Where:    A represents the  amplitude .    ω represents angular velocity.    t represents the  period .    ø represents the  phase shift .     Also, the  period  of a  sine wave  is given by:  t = 2π/ω  2 = 2π/ω  ω = 2    Substituting the given parameters into the equation, we have;  y = 3sin(2t + π/2)    At t = 0, we have:  y = 3sin(2(0) + π/2)  y = 3sin(π/2)  y = 3sin(90)  y = 3 × 1   y  =  3 .    In conclusion, we can logically deduce that the  y-intercept  of this  sine function  is equal to  3 .      Read more on  phase shift  here: https://brainly.com/question/27692212    #SPJ1

How to determine the y-intercept of this function?

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