Question A sine function has an amplitude of 3, a period of pi, and a phase shift of pi/2. What is the y-intercept of the function? A. 3 B.0 C.-3 D. pi/4

Based on the calculations, we can logically deduce that the y-intercept of this sine function is equal to: A. 3. Given the following data: Amplitude = 3 Period = π Phase shift = π/2 How to determine the y-intercept of this function? Mathematically, a sine function is modeled by this equation: y = Asin(ωt + ø) Where: A represents the amplitude. ω represents angular velocity. t represents the period. ø represents the phase shift. Also, the period of a sine wave is given by: t = 2π/ω 2 = 2π/ω ω = 2 Substituting the given parameters into the equation, we have; y = 3sin(2t + π/2) At t = 0, we have: y = 3sin(2(0) + π/2) y = 3sin(π/2) y = 3sin(90) y = 3 × 1 y = 3. In conclusion, we can logically deduce that the y-intercept of this sine function is equal to 3. Read more on phase shift here: https://brainly.com/question/27692212 #SPJ1 Log in to Reply

y-interceptof thissine functionis equal to: A.3.Given the following data:## How to determine the y-intercept of this function?

sine functionis modeled by thisequation:Where:amplitude.period.phase shift.periodof asine waveis given by:y=3.y-interceptof thissine functionis equal to3.phase shifthere: https://brainly.com/question/27692212