Question

A simple pendulum is 1.15 meters long and has a period of 6.29 seconds. The pendulum is on an unknown planet. What is the acceleration of gravity of the Unknown Planet

Answers

  1. Answer:

    The value of the acceleration of gravity of the Unknown Planet = 1.14 \frac{m}{s^{2} }

    Explanation:

    length of the pendulum (L)= 1.15 m

    Time period (T)= 6.29 seconds

    We know that time period  of a simple pendulum is given by

    ⇒ T = 2\pi × \sqrt\frac{L}{g}

    put the values in the above formula we get

    ⇒ T = 2\pi × \sqrt \frac{1.15}{g}

    ⇒ 6.29 = 2\pi × \sqrt \frac{1.15}{g}

    By solving the above equation we get

    ⇒ g = 1.14 \frac{m}{s^{2} }

    This is the value of the acceleration of gravity of the Unknown Planet.

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