Question A proton is 0.9 meters away from a 1.4 C charge. What is the magnitude of the electric force between the proton and the charge

Answer: F = 2.49 x 10⁻⁹ N Explanation: The electrostatic force between two charged bodies is given by Colomb’s Law: where, F = Electrostatic Force = ? k = colomb’s constant = 9 x 10⁹ N.m²/C² q₁ = charge on proton = 1.6 x 10⁻¹⁹ C q₂ = second charge = 1.4 C r = distace between charges = 0.9 m Therefore, F = 2.49 x 10⁻⁹ N Reply

Answer:F = 2.49 x 10⁻⁹ N

Explanation:The electrostatic force between two charged bodies is given by Colomb’s Law:

where,

F = Electrostatic Force = ?

k = colomb’s constant = 9 x 10⁹ N.m²/C²

q₁ = charge on proton = 1.6 x 10⁻¹⁹ C

q₂ = second charge = 1.4 C

r = distace between charges = 0.9 m

Therefore,

F = 2.49 x 10⁻⁹ N31.5N

I have confirmed it is the right answer.