A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.What is the specific heat of the substance?
Question
Question
A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.What is the specific heat of the substance?
Answer:
0.3832
Explanation:
Givens
m = 437.2 grams
c = ?
delta t = 69.8 – 19.3
H = 8460 J
Formula
H = m*c*Δt
Solution
8460 = 437.2 * c * (69.8 – 19.3)
8460 = 437.2 * c * 50.5
8460 = 22078.6 * c
c = 8460 / 22078,6
c = .3832 J / (oC * gr)