A person standing close to the edge on top of a 72-foot building throws a ball vertically upward. The

quadratic function h = – 16ť+ 136t + 72 models the ball’s height about the ground, h, in feet, t seconds after it was thrown.

a) What is the maximum height of the ball?

feet

b) How many seconds does it take until the ball hits the ground?

seconds

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Answer:I hope this helps.

Step-by-step explanation:h(t) = -16t2 + 108t + 28

(a)

Maximum height occurs at the vertex of the height-vs.-time parabola, which is at

t = -108/[2(-16)] sec = ? sec

Evaluate h(t) at this value of t to get hmax.

(b)

Set h(t) = 0 and solve the quadratic equation for t. You will get a positive and a negative solution. Discard the negative solution, since time starts at t = 0.