A person standing close to the edge on top of a 72-foot building throws a ball vertically upward. The
quadratic function h = – 16ť+ 136t + 72 models the ball’s height about the ground, h, in feet, t seconds after it was thrown.
a) What is the maximum height of the ball?
feet
b) How many seconds does it take until the ball hits the ground?
seconds
Question
Answer:
I hope this helps.
Step-by-step explanation:
h(t) = -16t2 + 108t + 28
(a)
Maximum height occurs at the vertex of the height-vs.-time parabola, which is at
t = -108/[2(-16)] sec = ? sec
Evaluate h(t) at this value of t to get hmax.
(b)
Set h(t) = 0 and solve the quadratic equation for t. You will get a positive and a negative solution. Discard the negative solution, since time starts at t = 0.