Question

A person has a bag of coins.

4/13 of the coins are pennies

1/4 of the coins that are not pennies, are nickels

The rest are dimes. If there is $8.10 in dimes, how much total money is in the bag of coins? Answers 1. thongdat2 Answer:$15.6
Step-by-step explanation:
First, let’s assume that x is the total money in the bag of coins.
1. x = total money
4/13 of the coins are pennies, so 4/13 of x equals to the number of pennies.
4/13(x) = P (pennies)
What is left that is not pennies is 9/13(x). And out of these, 1/4 are nickels. Which means:
1/4(9/13[x]) = N (nickels)
If 1/4 of the remaining are nickels, then 3/4 are dimes. So:
3/4(9/13[x]) = $8.10 (dimes’ value) After calculating the one with the value: 27/52(x) =$8.10
27x = $8.10 times 52 x = ($8.10 times 52)/27
x = 52 x $0.3 x =$15.6
Ans. The value of the bag of coins is $15.6 Reply 2. mocmien2 The answer is$15.06