A particular bird’s eye can just distinguish objects that subtend an angle no smaller than about 4.0×10^-4 rads.
(a) How many degrees is this?
(b) How small an object can the bird just distinguish when flying at a height of 160 m
Please show work, thank you.
Answer:
Part a)
Angle in degree is given as
[tex]\theta = 0.023 ^o[/tex]
Part b)
Size of the object is
[tex]Length = 0.064 m[/tex]
Explanation:
Part a)
As we know that
180 degree = [tex]\pi[/tex] radian
so we have
[tex]\theta = 4.0 \times 10^{-4} rad[/tex]
so we have
[tex]\theta = 4.0 \times 10^{-4} \times \frac{180}{\pi}[/tex]
[tex]\theta = 0.023 ^o[/tex]
Part b)
As we know that the relation of angle with radius is
[tex]\theta = \frac{arc}{radius}[/tex]
[tex]4 \times 10^{-4} = \frac{Length}{160}[/tex]
[tex]Length = 0.064 m[/tex]