Question A parabola, with its vertex at the origin, has a directrix at y = 3. which statements about the parabola are true? select two options.

The correct options about parabola are: The focus is located at (0,–3). The parabola can be represented by the equation x^2 = –12y. According to the statement we have given that the vertex is at the origin and directrix at y = 3. and from these given information and we have to find the all abot the parabola like its focus point etc. So, We know that the equation of parabola is (x-h)^2 = 4p(y-k) Here The vertex is (h,k). and the focus is at (h,k+p). and the directrix is y(k – p.) So, From the given information Vertex at the origin means that h=0 and k=0 Directrix at y = 3 means that p=-3 Directrix at the y-axis means the parabola opens upwards. Thus, the focus is: (0,-3) And The p-value becomes : 4(-3) = -12. And from all these the equation of the parabola is becomes (x)^2 = -12y So, The correct options about parabola are: The focus is located at (0,–3). The parabola can be represented by the equation x^2 = –12y. Learn more about Parabola here https://brainly.com/question/4061870 Disclaimer: The question was incomplete. Please find the full content Below. Question: A parabola, with its vertex at the origin, has a directrix at y = 3. Which statements about the parabola are true? Select two options. The focus is located at (0,–3). The parabola opens to the left. The p value can be determined by computing 4(3). The parabola can be represented by the equation x2 = –12y. The parabola can be represented by the equation y2 = 12x. #SPJ4 Log in to Reply

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