A money box contains only 10-cent
and 20-cent coins. There are 33
coins with a total value of $4.60.
How many coins of each?
Question
Question
A money box contains only 10-cent
and 20-cent coins. There are 33
coins with a total value of $4.60.
How many coins of each?
Answer:
Below in bold.
Step-by-step explanation:
x + y = 33 where x = 10 cent coin and y = 20 cent coin
10x + 20y = 460
Multiply first equation by 10:
10x + 10y = 330
Subtract this from the second equation:
10y = 130
y = 13
So there are 13 20c coins
and 33 – 13 = 20 10c coins.
20 ten cents and 13 twenty cents
This is a real logic problem you just need to trial and error