Question A money box contains only 10-cent and 20-cent coins. There are 33 coins with a total value of $4.60. How many coins of each?

Answer: Below in bold. Step-by-step explanation: x + y = 33 where x = 10 cent coin and y = 20 cent coin 10x + 20y = 460 Multiply first equation by 10: 10x + 10y = 330 Subtract this from the second equation: 10y = 130 y = 13 So there are 13 20c coins and 33 – 13 = 20 10c coins. Log in to Reply

20 ten cents and 13 twenty cents This is a real logic problem you just need to trial and error Log in to Reply

Answer:Below in bold.Step-by-step explanation:x + y = 33 where x = 10 cent coin and y = 20 cent coin

10x + 20y = 460

Multiply first equation by 10:

10x + 10y = 330

Subtract this from the second equation:

10y = 130

y = 13

So there are

1320c coinsand 33 – 13 =

2010c coins.20 ten cents and 13 twenty cents

This is a real logic problem you just need to trial and error