Question A mass weighing 16 pounds is attached to a spring whose spring constant is 36 lb/ft. what is the period of simple harmonic motion?

The period of simple harmonic motion is T = 4.19 seconds: For given question, A mass weighing 16 pounds is attached to a spring whose spring constant is 36 lb/ft. So, we have mass (m) = 16 pounds spring constant (k) = 36 lb/ft. Let T be the period of simple harmonic motion. Using the formula for the period of simple harmonic motion, ⇒ T = 2π√(m/k) ⇒ T = 2 × π × √(16/36) ⇒ T = 2 × π × √(0.444) ⇒ T = 2 × π × 0.666 ⇒ T = 1.333 × π ⇒ T = 4.19 seconds Therefore, the period of simple harmonic motion is T = 4.19 seconds Learn more about the simple harmonic motion here: https://brainly.com/question/17315536 #SPJ4 Log in to Reply

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