Answers

1. The period of simple harmonic motion is T = 4.19 seconds:

   For given question,

   A mass weighing 16 pounds is attached to a spring whose spring constant is 36 lb/ft.

   So, we have mass (m) = 16 pounds

   spring constant (k) = 36 lb/ft.

   Let T be the period of simple harmonic motion.

   Using the formula for the period of simple harmonic motion,

   ⇒ T = 2π√(m/k)

   ⇒ T = 2 × π × √(16/36)

   ⇒ T = 2 × π × √(0.444)

   ⇒ T = 2 × π × 0.666

   ⇒ T = 1.333 × π

   ⇒ T = 4.19 seconds

   Therefore, the period of simple harmonic motion is T = 4.19 seconds

   Learn more about the simple harmonic motion here:

   https://brainly.com/question/17315536

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