A line passes through the points (–6, –7) and (–3, 1). What is its equation in slope-intercept form?

Write your answer using integers, proper fractions, and improper fractions in simplest form.

A line passes through the points (–6, –7) and (–3, 1). What is its equation in slope-intercept form?

Write your answer using integers, proper fractions, and improper fractions in simplest form.

Answer:

y = 8/3(x) + 9

Step-by-step explanation:

The general equation of a straight line is slope intercept form is;

y = mx + b

where m is the slope and b is the y-intercept

To get the slope, we use the slope equation

we have this as:

m = (y2-y1)/(x2-x1)

(x1,y1) = (-6,-7)

(x2,y2) = (-3,1)

m = (1+7)/(-3 + 6) = 8/3

so we have the equation as;

y = 8/3(x) + b

to get the value of b, we make use of any of the two points

We substitute the coordinates of the two points into the equation

Let us use the point (-3,1)

Thus;

1 = 8/3(-3) + b

1 = -8 + b

b = 1 + 8

b = 9

So the full equation is;

y = 8/3(x) + 9