A line passes through the point (-4,-5) and had a slope of 5/2. Write an equation in slope-intercept form
-
Step-by-step explanation:as we have a point and the slope, we can start with the point-slope form and then transform.the point-slope form isy – y1 = a(x – x1)(x1, y1) being a point on the line, a being the slope.the slope-interceot form isy = ax + ba being the slope again, b being the y-intercept (the y value for x = 0).so, we havey – -5 = 5/2 × (x – -4)y + 5 = 5/2 × (x + 4) = 5x/2 + 5×4/2 = 5x/2 + 10y = 5x/2 + 5ory = (5/2)x + 5and this is already the slope-intercept form. all done.