Question A line passes through the point (-4,-5) and had a slope of 5/2. Write an equation in slope-intercept form

Step-by-step explanation: as we have a point and the slope, we can start with the point-slope form and then transform. the point-slope form is y – y1 = a(x – x1) (x1, y1) being a point on the line, a being the slope. the slope-interceot form is y = ax + b a being the slope again, b being the y-intercept (the y value for x = 0). so, we have y – -5 = 5/2 × (x – -4) y + 5 = 5/2 × (x + 4) = 5x/2 + 5×4/2 = 5x/2 + 10 y = 5x/2 + 5 or y = (5/2)x + 5 and this is already the slope-intercept form. all done. Reply

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