Question

A line passes through the point (-4,-5) and had a slope of 5/2. Write an equation in slope-intercept form

Answers

  1. Step-by-step explanation:
    as we have a point and the slope, we can start with the point-slope form and then transform.
    the point-slope form is
    y – y1 = a(x – x1)
    (x1, y1) being a point on the line, a being the slope.
    the slope-interceot form is
    y = ax + b
    a being the slope again, b being the y-intercept (the y value for x = 0).
    so, we have
    y – -5 = 5/2 × (x – -4)
    y + 5 = 5/2 × (x + 4) = 5x/2 + 5×4/2 = 5x/2 + 10
    y = 5x/2 + 5
    or
    y = (5/2)x + 5
    and this is already the slope-intercept form. all done.

    Reply

Leave a Comment