A gold mine has two elevators, one for equipment and another for the miners. The equipment elevator descends 7 feet per second. The elevator for the miners descends 17 feet per second. One day, the equipment elevator begins to descend. After 31 seconds, the elevator for the miners begins to descend. What is the position of each elevator relative to the surface after another 14 seconds? At that time, which elevator is deeper?

positionsof each elevator relative to the surface after another 14 seconds are: the equipment elevator is at 315 feet and the minor elevator is at 238 feet. So, the minor elevator isdeeperthan the equipment elevator.## What is the speed formula?

speedformula is written asdistance= speed × time ortime= distance/speed## Calculation:

speedof the equipment elevator is Se = 7 feet/sec (descends)speedof the minor elevator is Sm = 17 feet/sec (descends)positionsof both elevators after another 14 sec from their begin to descend are calculated as follows:distancethe equipment elevator descends isdistanceminor elevator descends isminor elevatoris deeper than theequipment elevator.speed-distance-timehere: