Question A gas has a solubility of 0.66 g/L at 10.0 atm. What is the pressure on a 1.0 L samples that contains 1.5 g of gas

Answer: “22.73 atm” is the correct answer. Explanation: Given: Solubility, [tex]S_1=0.66 \ g/L[/tex] [tex]S_2=1.5 \ g/L[/tex] Pressure, [tex]P_1=10.0 \ atm[/tex] [tex]P_2=?[/tex] By using Henry’s law, ⇒ [tex]\frac{S_1}{P_1} =\frac{S_2}{P_2}[/tex] or, ⇒ [tex]P_2=\frac{S_2 P_1}{S_1}[/tex] By putting the values, we get ⇒ [tex]=\frac{1.5\times 10.0}{0.66}[/tex] ⇒ [tex]=\frac{15}{0.66}[/tex] ⇒ [tex]=22.73\ atm[/tex] Log in to Reply

Answer:“

22.73 atm” is the correct answer.Explanation:Given:

Solubility,[tex]S_1=0.66 \ g/L[/tex]

[tex]S_2=1.5 \ g/L[/tex]

Pressure,[tex]P_1=10.0 \ atm[/tex]

[tex]P_2=?[/tex]

By using Henry’s law,⇒ [tex]\frac{S_1}{P_1} =\frac{S_2}{P_2}[/tex]

or,

⇒ [tex]P_2=\frac{S_2 P_1}{S_1}[/tex]

By putting the values, we get

⇒ [tex]=\frac{1.5\times 10.0}{0.66}[/tex]

⇒ [tex]=\frac{15}{0.66}[/tex]

⇒ [tex]=22.73\ atm[/tex]