A force of 19 Newton’s is applied on a cart of 2 kilograms and it experiences a frictional force of 1.7 Newton’s what acceleration of the cart
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Question
A force of 19 Newton’s is applied on a cart of 2 kilograms and it experiences a frictional force of 1.7 Newton’s what acceleration of the cart
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Answer:
ans: 8.65 m/s^2
Explanation:
since force is vector so for resultant
(F)resultant = [ (F1)^2 + |F1|•|F2|•cos180° + (F2)^2]^(1/2)
= (F1) – (F2)
= 19 – 1.7
= 17.3
SO,
force = ma
17.3 = 2×a
so, a= 8 65 m/s^2