Question A force of 19 Newton’s is applied on a cart of 2 kilograms and it experiences a frictional force of 1.7 Newton’s what acceleration of the cart

Answer: ans: 8.65 m/s^2 Explanation: since force is vector so for resultant (F)resultant = [ (F1)^2 + |F1|•|F2|•cos180° + (F2)^2]^(1/2) = (F1) – (F2) = 19 – 1.7 = 17.3 SO, force = ma 17.3 = 2×a so, a= 8 65 m/s^2 Log in to Reply

Answer:ans: 8.65 m/s^2

Explanation:since force is vector so for resultant

(F)resultant = [ (F1)^2 + |F1|•|F2|•cos180° + (F2)^2]^(1/2)

= (F1) – (F2)

= 19 – 1.7

= 17.3

SO,

force = ma

17.3 = 2×a

so, a= 8 65 m/s^2