A disk of radius 25.0cm turns about an axis through the center. The pull on the string produces a linear acceleration a(t)=At on the ball The disk starts from rest and after 3 seconds, linear a(3)=1.80m/s2. Find A and then write an expression for the angular acceleration α(t).

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Answer:The value for A is A= 0.6

The angular acceleration is

Explanation:From the question we are told that

The radius of the disk is

The linear acceleration is

At time

Generally angular acceleration is mathematically represented as

Now at t = 3 seconds

a(3) = A * 3

=> 1.80 = A * 3

=.> A = 0.6

So therefore

a(t) = 0.6 t

Now substituting this into formula for angular acceleration

substituting for r