A diagonal aluminum alloy tension rod of diameter d and initial length l is used in a rectangularframe to prevent collapse. The rod can safe

A diagonal aluminum alloy tension rod of diameter d and initial length l is used in a rectangularframe to prevent collapse. The rod can safely support a tensile stress of sallow. If d 5 0.5 in,l 5 8 ft, and sallow 5 20 kpsi, determine how much the rod must be stretched to develop thisallowable stress.

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  1. Answer:

    The stretched length is 0.18816 in.

    Explanation:

    Given that,

    Distance = 0.5 in

    length = 8 ft

    Tensile stress = 20 kpsi

    We need to calculate the stretched length

    Using formula of length

    [tex]\Delta L=\dfrac{PL}{AE}[/tex]

    [tex]\Delta L=\sigma\times\dfrac{L}{E}[/tex]

    Where, [tex]\sigma[/tex] = Tensile stress

    L = length

    E = young’s modulus of aluminum

    Put the value into the formula

    [tex]\Delta L= 20\times10^3\dfrac{8}{10.2\times10^{6}}[/tex]

    [tex]\Delta L= 0.01568\ ft[/tex]

    [tex]\Delta L=0.01568\times12[/tex]

    [tex]\Delta L=0.18816\ in[/tex]

    Hence, The stretched length is 0.18816 in.

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