A dealer bought some 9-volt batteries for $2,400. She sold them for $5,600, making a proﬁt of $1.60 on each

battery. How many batteries were involved in the deal? a.3,500 b.1,500 c.5,000 d.2,000 e.2,500

battery. How many batteries were involved in the deal? a.3,500 b.1,500 c.5,000 d.2,000 e.2,500

proﬁtof $1.60 on each battery.2,500 batterieswere involved in the deal.9-volt batteriesfor $2,400 and she sold them for $5,600. To find out how many batteries were involved, we need to calculate how much she made from each battery. We can do this by subtracting the cost of the batteries from theselling priceand then dividing it by the number of batteries.Profitper battery = $5,600 – $2,400 = $3,200. Number of batteries = $3,200/$1.60 = 2,500. Therefore, thedealer bought 2,500 batteries.profithere