Question

A coin bank contains nickels and dimes. The
number of dimes is 10 less than twice the
number of nickels. The total value of all
coins is $2.75. Find the number of each type
of coins in the bank. Show work

Answers

  1. Answer:  15 nickels and 20 dimes

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    Work Shown:
    n = number of nickels
    d = number of dimes
    d = 2n-10 since “number of dimes is 10 less than twice the number of nickels”
    0.05n = value of all the nickels in dollars
    0.10d = value of all the dimes in dollars
    0.05n+0.10d = total value in dollars
    0.05n+0.10d = 2.75
    Multiply all three terms by 100 to move the decimal point over two spots to the right. We get this new updated equation
    5n+10d = 275
    ———
    Now plug in d = 2n-10 and solve for n
    5n+10d = 275
    5n+10(2n-10) = 275
    5n+20n-100 = 275
    25n-100 = 275
    25n = 275+100
    25n = 375
    n = 375/25
    n = 15
    There are 15 nickels.
    Use this to find the value of d.
    d = 2n-10
    d = 2*15-10
    d = 30-10
    d = 20
    There are 20 dimes.
    ———–
    Check:
    5n = 5*15 = 75 cents from just the nickels only
    10d = 10*20 = 200 cents from just the dimes only
    5n+10d = 75+200 = 275 cents total
    275 cents = 275/100 = $2.75
    This confirms the answers.

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