A cheetah is running in a straight line in pursuit of prey. The cheetah’s mass is 63.9 kg. Through its running motion, assume the cheetah experiences a constant forward force of 609.1 N. Also, assume the cheetah experiences a constant 107.9 N air resistance force that is opposite its motion. What is the magnitude of the cheetah’s acceleration, in units of m/s2?
Question
Answer:
a = 7.84 m / s²
Explanation:
For this exercise let’s use Newton’s second law
F – fr = m a
indicate that the force is F = 609.1 N and the friction force is fr = 107.9 N and is constant
a = [tex]\frac{F – fr}{m}[/tex]
let’s calculate
a = [tex]\frac{ 609.1 – 107.9 }{63.9}[/tex]
a = 7.84 m / s²