Question

A Carnot air conditioner takes energy from the thermal energy of a room at 61°F and transfers it as heat to the outdoors, which is at 98°F. For each joule of electric energy required to operate the air conditioner, how many joules are removed from the room?

Answers

  1. Answer:

    14.07 units of joules is removed for each joules of electricity used

    Explanation:

    The heated room temperature T_{c} = 61 °F

    The outside temperature T_{h} = 98 °F

    For conversion from fahrenheit to kelvin we use the equation

    (32°F − 32) × 5/9 + 273.15

    T_{c} = 289.26

    T_{h} = 309.82

    For air conditioning,

    COP = \frac{T_{c} }{T_{h} -T_{c} }

    COP = \frac{289.26 }{309.82 -289.26 }  = 14.07

    This means that 14.07 units of joules is removed for each joules of electricity used

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