Question a car is traveling at 20m/s along a road. a child runs out into the road 50 m ahead and the car driver steps on the break. what must the car’s decelaration be if the car is to stop just before it reaches the child.

Answer: 4 m/s² Explanation: [tex]v {}^{2} = {u}^{2} + 2as \\ 0 {}^{2} = {20}^{2} + 2a(50) \\ a = – 4ms {}^{ – 2} [/tex] Therefore, deceleration = 4 m/s² Log in to Reply

Answer:4m/s²Explanation:[tex]v {}^{2} = {u}^{2} + 2as \\ 0 {}^{2} = {20}^{2} + 2a(50) \\ a = – 4ms {}^{ – 2} [/tex]

Therefore,

deceleration = 4 m/s²