Question

A body is thrown vertically upward and the height travelled by it is 200m , find the initial velocity and time required to reach maximum height ?
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Answers

  1. Answer:

    Initial velocity(u)=62.6 m/s^2

    Time(t)=6.39 seconds

    Solution,

    Displacement(s)=200 m

    Initial velocity (u)=?

    Final velocity(v)=0 m/s^2

    acceleration due to gravity(g)=–9.8 m/s^2

    now,

    {v}^{2} = {u}^{2} + 2as \\ {(0)}^{2} = {u}^{2} + 2 \times ( - 9.8) \times 200 \\ {u}^{2} = 2 \times 9.8 \times 200 \\ {u}^{2} = 3920 \\ u = \sqrt{3920} \\ u = \sqrt{ {62.6}^{2} } \\ u = 62.6 \: metre \: per \: second

    Again,

    Finding time taken,

    v = u + at \\ t = \frac{v - u}{a} \\ = \frac{0 - 62.6}{ - 9.8} \\ = \frac{ - 62.6}{ - 9.8} \\ = 6.39 \: seconds

    Hope this helps...

    Good luck on your assignment...

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