A barbell spins around a pivot at its center at A. The barbell consists of two small balls, each with mass 450 grams (0.45 kg), at the ends

Question

A barbell spins around a pivot at its center at A. The barbell consists of two small balls, each with mass 450 grams (0.45 kg), at the ends of a very low mass rod of length d = 20 cm (0.2 m; the radius of rotation is 0.1 m). The barbell spins clockwise with angular speed 120 radians/s.

What is the speed of ball 1?

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Nho 4 years 2021-07-22T05:51:44+00:00 1 Answers 165 views 0

Answers ( )

  1. lethu
    0
    2021-07-22T05:53:15+00:00
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    Answer:

    The speed of ball is 12 \frac{m}{s}

    Explanation:

    Given:

    Mass of ball m = 0.45 kg

    Radius of rotation r = 0.1 m

    Angular speed \omega = 120 \frac{rad}{s}

    Here barbell spins around a pivot at its center and barbell consists of two small balls,

    From the formula of speed in terms of angular speed,

      v = r \omega

    Where v = speed of ball

      v = 120 \times 0.1

      v = 12 \frac{m}{s}

    Therefore, the speed of ball is 12 \frac{m}{s}

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