Question A bag of m&m’s has 4 red, 7 green, 8 blue, and 6 yellow m&m’s. what is the probability of randomly pickinga blue or green?

Step-by-step explanation: a probability is always desired cases over total possible cases. the bag has 4 + 7 + 8 + 6 = 25. so, when we pick a random M&M we have total 25 possible outcomes. the desired cases are to pick a green or a blue M&M. that means these are 7+8 = 15 cases. the probability to pick one or of the desired cases is 15/25 = 3/5 = 0.6 Reply

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