Question a bag of ice cubes absorbs 149,000 J of heat, which causes its temperature to increase by 5.23 degrees celsius. what is the mass of the ice in the bag? Ice=c=2000J/(kg*c) (unit=kg)

Answer: 14.3kg Explanation: Given parameters: Quantity of heat = 149000J Change in temperature = 5.23°C specific heat of the ice = 2000J/kg°C Unknown: Mass of the ice in the bag = ? Solution: The heat capacity of a substance is given as: H = m c Ф H is the heat capacity m is the mass c is the specific heat Ф is the temperature change; since m is the unknown, we make it the subject of the expression; m = H/ mФ m = [tex]\frac{149000}{2000 x 5.23}[/tex] = 14.3kg Log in to Reply

Answer: 14.2447

Explanation:

Answer:14.3kgExplanation:Given parameters:

Quantity of heat = 149000J

Change in temperature = 5.23°C

specific heat of the ice = 2000J/kg°C

Unknown:

Mass of the ice in the bag = ?

Solution:

The heat capacity of a substance is given as:

H = m c Ф

H is the heat capacity

m is the mass

c is the specific heat

Ф is the temperature change;

since m is the unknown, we make it the subject of the expression;

m = H/ mФ

m = [tex]\frac{149000}{2000 x 5.23}[/tex] =

14.3kg