Question A and B are friends and their ages differ by 4 years, A being the elder. A’s father D, is twice as old as A, and B is twice as old as his sister C. The age of D and and C differ by 38 years. Find the ages of A and B.

Answer: Step-by-step explanation: A = B+4 D = 2A B = 2C D-C = 38 2A – B/2 = 38 2(B+4) – B/2 = 38 4B+16 – B = 79 3B = 63 B = 21 A = B+4 = 25 Log in to Reply

Answer:Step-by-step explanation:A = B+4

D = 2A

B = 2C

D-C = 38

2A – B/2 = 38

2(B+4) – B/2 = 38

4B+16 – B = 79

3B = 63

B = 21

A = B+4 = 25