Question A 6-gallon container that is 40% juice is added to a 3-gallon container that is 50% juice. What percent of the resulting mixture is juice?

The percent of the resulting mixture which is juice as required in the task content is; 43.33%. What percent of the resulting mixture is juice according to the given information? It follows from the task content that the percent of the resulting mixture which is juice is to be determined given the information. As evident in the task content; The 6-gallon container has 40% juice while a 3-gallon container that is 50% juice. Therefore, it can be inferred from the juice balance of the mixing arrangement that; ( 40% of 6 ) + ( 50% of 3 ) = (x% of 9) since; the total mixture has volume; 6 + 3 = 9. Therefore, it follows from evaluation that; (0.4 × 6) + (0.5 × 3) = 0.01x × 9 2.4 + 1.5 = 0.09x 0.09x = 3.9 x = 3.9 / 0.09 x = 43.33%. On this note, the percent of the resulting mixture which is juice is; 43.33%. Read more on percentages; https://brainly.com/question/26150306 #SPJ1 Reply

percentof the resultingmixturewhich is juice as required in the task content is; 43.33%.## What percent of the resulting mixture is juice according to the given information?

percentof the resultingmixturewhich is juice is to be determined given the information.total mixturehas volume; 6 + 3 = 9.percentof the resulting mixture which is juice is; 43.33%.percentages;