A 4.2 cm diameter circular loop of wire is in a 1.14 T magnetic field. The loop is removed from the field in 0.18 s. Assume that the loop is perpendicular to the magnetic field. What is the average induced emf?
Question
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Given Information:
Diameter of loop = d = 4.2 cm = 0.042 m
Magnetic field = B = 1.14 T
Time = Δt = 0.18 s
Required Information:
EMF = ?
Answer:
EMF = 0.417 V
Explanation:
The Faraday’s Law of Induction relates induced EMF and the time rate of change of magnetic flux which is given by
EMF = -ΔФ/Δt
EMF = -AΔB/Δt
Where A is the area of circular loop and ΔB is the change in magnetic field
A = πr²
A = π(d/2)²
A = π(0.042/2)²
A = 0.0659 m²
EMF = -0.0659*(0 – 1.14)/0.18
EMF = -0.0659*(-1.14)/0.18
EMF = 0.417 V
Therefore, the average induced EMF in circular loop of wire is 0.417 Volts