A 150kg motorcycle starts from rest and accelerates at a constant rate along with a distance of 350m. The applied force is 250N and the coefficient of kinetic friction is 0.03. What is the net force applied to the motorcycle?

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Answer:205NExplanation:The net force (F) is the difference between the applied force() and the kinetic frictional force(). i.e

F = – —————–(i)

Note that;

= μmg

Where;

μ = coefficient of kinetic friction

m = mass of the body

g = acceleration due to gravity = 10m/s²

Equation (i) then becomes;

F = – μmg ——————-(ii)

Given from question;m = mass of motorcycle = 150kg

μ = 0.03

= 250N

Substitute these values into equation (ii) as follows;

F = 250 – (0.03 x 150 x 10)

F = 250 – (45)

F = 205N

Therefore, the net force applied to the motorcycle is

205N