Question

A 1000-kg car is driving toward the north along a straight horizontal road at a speed of 20.0 m/s. The driver applies the brakes and the car comes to a rest uniformly in a distance of 160 m. What are the magnitude and direction of the net force applied to the car to bring it to rest?

Answers

  1. Answer:

    Force applied to stop the car = 1,250 N

    Explanation:

    Given:

    Mass of car (M) = 1,000 kg

    Initial velocity (U) = 20 m/s

    Final velocity (V) = 0 m/s

    Distance (S) = 160 m

    Find:

    Force applied to stop the car.

    Computation:

    v^2 = u^2 + 2as\\\\0^2=20^2+2(a)(160)\\\\0=400+320(a)\\\\Acceleration = a = -1.25m/s^2\\\\Force = ma \\\\Force= 1,000(1.25)\\\\Force = 1,250 N

    Force applied to stop the car = 1,250 N

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