Question

a 10 kg block is attached to a light chord that is wrapped around the pulley of an electric motor. at what rate is the motor doing work when it is pulling the block upward w an instantaneous speed of 3 m/s and an upward acc of 2 m/s^2?

Answers

  1. Answer:

    The rate of work is 360 W

    Explanation:

    Given:

    Speed of block v = 3 \frac{m}{s}

    Upward acceleration of block a = 2 \frac{m}{s^{2} }

    Mass of block m = 10 kg

    First Find the force act on block due to gravity

      F = M (a + g)

    Where g = 10 \frac{m}{s^{2} }

      F = 10 \times (10+2)

      F = 120 N

    For finding at what rate motor doing work when it is pulling the block upward,

      P = F.v

      P = 120 \times 3

      P = 360 W

    Therefore, the rate of work is 360 W

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