A 0.50 kg object is attached to a spring with force constant 157 N/m so that the object is allowed to move on a horizontal frictionless surface. The object is released from rest when the spring is compressed 0.19 m.(a) Find the force on the object.1 N
(b) Find its acceleration at that instant 2 m/s2
Explanation:
We have,
Mass of an object is 0.5 kg
Force constant of the spring is 157 N/m
The object is released from rest when the spring is compressed 0.19 m.
(A) The force acting on the object is given by :
F = kx
[tex]F=157\times 0.19\\\\F=29.83\ N[/tex]
(B) The force is simply given by :
F = ma
a is acceleration at that instant
[tex]a=\dfrac{F}{m}\\\\a=\dfrac{29.83}{0.5}\\\\a=59.66\ m/s^2[/tex]