Question

A 0.50 kg object is attached to a spring with force constant 157 N/m so that the object is allowed to move on a horizontal frictionless surface. The object is released from rest when the spring is compressed 0.19 m.(a) Find the force on the object.1 N
(b) Find its acceleration at that instant 2 m/s2

Answers

  1. Explanation:

    We have,

    Mass of an object is 0.5 kg

    Force constant of the spring is 157 N/m

    The object is released from rest when the spring is compressed 0.19 m.

    (A) The force acting on the object is given by :

    F = kx

    F=157\times 0.19\\\\F=29.83\ N

    (B) The force is simply given by :

    F = ma

    a is acceleration at that instant

    a=\dfrac{F}{m}\\\\a=\dfrac{29.83}{0.5}\\\\a=59.66\ m/s^2

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