1/2 + (1/2)^2 +(1/2)^3 +….+ (1/2)^36

1/2 + (1/2)^2 +(1/2)^3 +….+ (1/2)^36

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  1. Đáp án:

     

    Giải thích các bước giải:

     Đặt `A=1/2 + (1/2)^2 +(1/2)^3 +….+ (1/2)^36`

    `=>2A=1+1/2+1/(2^2)+….+1/(2^35)`

    `2A-A=A=1-1/(2^36)`

    Học tốt .-.

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  2. Đặt `A=1/2 + (1/2)^2 +(1/2)^3 +….+ (1/2)^36`

    `2A     =1+1/2+(1/2)^2+…+(1/2)^35`

    `2A-A =1-(1/2)^35`

    Hay `1/2 + (1/2)^2 +(1/2)^3 +….+ (1/2)^36=1-(1/2)^35`

    Reply

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