(x+1)^3+3x(x+2)+x^2(x-1)+5x^2(x-1)=15 help me!!!!! Cần gấp vote 5*

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1. `(x+1)^3+3x(x+2)+x^2(x-1)+5x^2(x-1)=15`

   `<=>x^3+3x^2+3x+1+3x^2+6x+x^3-x^2+5x^3-5x^2-15=0`

   `<=>(x^3+x^3+5x^3)+(3x^2+3x^2-x^2-5x^2)+(3x+6x)+(1-15)=0`

   `<=>7x^3+9x-14=0`

   `<=>` Nghiệm sấu lắm bạn.

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2. Giải thích các bước giải:

   `(x+1)^3+3x(x+2)+x^2(x-1)+5x^2(x-1)=15`

   `<=>x^3+3x^2+3x+1+3x^2+6x+x^3-x^2+5x^3-5x^2=15`

   `<=>x^3+3x^2+3x+1+3x^2+6x+x^3-x^2+5x^3-5x^2-15=0`

   `<=>7x^3+9x-14=0`

   `<=>….?`

    

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