A piano tuner detects 3 beats per second when she is tuning a string to a tuning fork of frequency 440 Hz. When she tightens the string, whi

Question

A piano tuner detects 3 beats per second when she is tuning a string to a tuning fork of frequency 440 Hz. When she tightens the string, which increases the frequency of the string, the frequency of the beats initially goes down, and as she keeps increasing the frequency of the string, the frequency of the beats starts to increase. What was the original frequency of the string

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Tài Đức 4 years 2021-08-19T09:26:09+00:00 1 Answers 28 views 0

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    2021-08-19T09:28:08+00:00

    Answer:

    F_o=437Hz

    Explanation:

    From the question we are told that:

    Frequency of Turning fork F_t=440Hz

    Number of beats detected n=3  

    Generally the equation for Original frequency F_o of the string  is mathematically given by

    F_o=F_t-F_b

    Where

    F_b Beat frequency

    F_b=1Hz*n\\F_b=1Hz*3

    Therefore

    F_o=440-3

    F_o=437Hz

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