A thin film of acetone (n=1.25) lies on the surface of a thick piece of water (n=1.30). White light shines down from air onto the thin layer

Question

A thin film of acetone (n=1.25) lies on the surface of a thick piece of water (n=1.30). White light shines down from air onto the thin layer of acetone. Destructive interference occurs for m=3 for a wavelength in air of 600 nm. What is the thickness of the thin film?

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Khánh Gia 4 years 2021-08-05T03:24:28+00:00 1 Answers 14 views 0

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    2021-08-05T03:26:20+00:00

    Answer:

    Explanation:

    The wave of light is being reflected two times while going from lower to higher refractive index mediums

    So there will be phase reversal two times .

    Condition of destructive index

    2 μ t = ( 2m+1) λ / 2

    Substituting the values

    2 x 1.25 x t = ( 2 x 3 + 1 ) x 600nm / 2

    2.5 t = 2100 nm

    t = 840 nm .

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