H-H + CI-Cl —> H-Cl + H-Cl

Question

H-H + CI-Cl —> H-Cl +
H-Cl

in progress 0
Orla Orla 4 years 2021-09-03T07:45:20+00:00 2 Answers 15 views 0

Answers ( )

  1. Dulcie
    0
    2021-09-03T07:46:33+00:00
    Reply

    What is that uhhhhhhhhhh

  2. ngocdiep
    0
    2021-09-03T07:46:51+00:00
    Reply

    Answer:

    Step 1

    H2(g) → 2 H(g)

    Cl2(g) → 2 Cl(g)

    Step 2

    2 H (g) + 2 Cl (g) → 2 HCl

    ΔH1 = +(436 kJ + 243 kJ) = +679 kJ

    ΔH2 = -2(431 kJ) = -862 kJ

    By applying Hess’s Law, ΔH = ΔH1 + ΔH2

    ΔH = +679 kJ – 862 kJ

    ΔH = -183 kJ

    Explanation:

    Estimate the change in enthalpy, ΔH, for the following reaction:

    H2 (g) + Cl2 (g) → 2 HCl (g)

    Solution

    To work this problem, think of the reaction in terms of simple steps:

    Step 1 The reactant molecules, H2 and Cl2, break down into their atoms.

    H2(g) → 2 H(g)

    Cl2(g) → 2 Cl(g)

    Step 2 These atoms combine to form HCl molecules.

    2 H (g) + 2 Cl (g) → 2 HCl (g)

    In the first step, the H-H and Cl-Cl bonds are broken. In both cases, one mole of bonds is broken. When we look up the single bond energies for the H-H and Cl-Cl bonds, we find them to be +436 kJ/mol and + 243 kJ/mol, therefore for the first step of the reaction:​

    ΔH1 = +(436 kJ + 243 kJ) = +679 kJ

    ΔH2 = -2(431 kJ) = -862 kJ

    By applying Hess’s Law, ΔH = ΔH1 + ΔH2

    ΔH = +679 kJ – 862 kJ

    ΔH = -183 kJ

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )