Question 9) through: (-5, 4) and (1, -2) A) y + 5 = 3(x+4) B) y+4=3(x+5) C) y – 4 = -(x + 5) D) y – 4 = 3(x+5)

The equation of the line that passes through the point (-5, 4) and (1, -2) is; C) y – 4 = -(x + 5) What is the Point-slope form? The equation of the straight line has its slope and given point. If we have a non-vertical line that passes through any point(x1, y1) and has a gradient m. then general point (x, y) must satisfy the equation y-y₁ = m(x-x₁) Where x₁ – x coordinate, y₁ – y coordinate, m – slope Point (-5, 4) and (1, -2) Then Slope m = (-2 – 4)/(1 + 5) m = -6/6 = -1 Now Write the equation as; y – 4 = -1(x + 5) Hence, the equation of the line is; C) y – 4 = -(x + 5) Learn more about equations here; brainly.com/question/25180086 #SPJ1 Reply

equationof thelinethat passes through thepoint(-5, 4) and (1, -2) is; C) y – 4 = -(x + 5)## What is the Point-slope form?

equationof thestraight linehas its slope and given point.point(x1, y1) and has agradientm. then general point (x, y) must satisfy the equationcoordinate, y₁ – y coordinate, m –slopePoint(-5, 4) and (1, -2)Slopem = (-2 – 4)/(1 + 5)equationas;equationof thelineis; C) y – 4 = -(x + 5)equationshere;