Question 8th/9th-95 POINTS+BRAINLIEST!!!!!!!! How do you write a quadratic equation in vertex form? Please explain the steps in simple language and use y=x²+6x+16 as an example.

Answer: In vertex form: y = 1(x – (-3))² + 7 Vertex: Minimum (-3, 7) Explanation: Vertex form: y = a(x – h)² + k Completing square (rules) : 1st rule: (x + d)² = x² + 2dx + d² and (x – d)² = x² – 2dx + d² 2nd rule: x² + 2dx = (x + d)² – d² and x² – 2dx = (x – d)² – d² Given equation: y = x² + 6x + 16 y = x² + 2(3)x + 3² + 7 y = (x + 3)² + 7 Into vertex form: y = 1(x – (-3))² + 7 From this identify: a = 1, h = -3, k = 7 Solution, vertex of this equation: Minimum (-3, 7) Reply

So you find the a and b in (x-a)^2+b. A is 3 and b is 7.

Answer:Explanation:Completing square (rules) :and(x – d)² = x² – 2dx + d²andx² – 2dx = (x – d)² – d²Given equation:Into vertex form:From this identify: