8 basketball teams enter a tournament. the first, second, and third-place teams win medals. in how many ways can the 8 teams finish 1st, 2nd, 3rd


  1. The number of ways in which the 8 teams finish found by permutation is 1st, 2nd, 3rd is 336.

    What is a permutation?

    A permutation would be a mathematical computation of the number of possible arrangements of a given set, in which the sequence of the arrangements is important.
    Now, according to the question,
    We have ten teams and want to understand number of times PERMUTATIONS OF 3 are possible.  For only a PERMUTATION, we want to consider how several positions we are selecting and how many options are available for each of those positions.
    So, given three options are;
    (# of choices for first) x (# of choices for second) x (# of choices for third)
    If there are originally 8 teams to pick from, then first place has 8 alternatives. When one of those is chosen for first, there are only 7 alternatives for second, and only 6 choices for third… and so on.
    8 × 7 × 6 = 336
    Therefor, here are 366 possible methods to choose first, second, and third place from the original eight teams.
    To know more about permutation, here


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