8. a laser is set up in the center of a laboratory as shown, and is mounted on a swivel that rotates at a rate of 6 revolutions per minute. determine the speed of the dot on the wall at the points (i) a and (ii) b.

The laser dot on the wall at point a moves at a pace of 6 times the circle’s diameter, while the laser dot at point (ii) moves at 6π radians per minute.

i. The equation for linear speed, can be used to calculate the speed of the laser dot on the wall at point a. The distance in this instance is equal to the diameter of the circle created by the rotation of the laser, and the amount of time required to transit it is equal to one revolution, or 1/6 of a minute. The diameter of the circle is divided by 1/6 of a minute or six times the circumference of the circle.

ii. The equation for angular speed is used to calculate the speed of the laser dot on the wall at position b. In this instance, the angle is 2 radians, and it takes 1/6 of a minute to cross that angle. Therefore, 2 radians divided by 1/6 of a minute, or 6π radians per minute, is the speed of the laser dot on the wall at point b.

6times the circle’s diameter, while the laser dot at point (ii) moves at6πradians per minute.linearspeed, can be used to calculate the speed of the laser dot on the wall at point a. The distance in this instance is equal to the diameter of the circle created by therotationof the laser, and the amount of time required to transit it is equal to one revolution, or 1/6 of a minute. The diameter of the circle is divided by1/6of a minute or six times the circumference of the circle.angularspeed is used to calculate the speed of the laser dot on the wall at position b. In this instance, the angle is2radians, and it takes1/6of a minute to cross that angle. Therefore, 2 radians divided by 1/6 of a minute, or6πradians per minute, is the speed of the laser dot on the wall at point b.linear and angularspeed here:#SPJ4