Question

6+2/3b=3/4b-4
smallest common multiple of 3 and 4 is 12
72+8b=9b-48?
_-72______-72_
8b=9b-120

What are my next steps and what are my mistakes?

Answers

  1. ​Answer:
    b=120
    Step-by-step explanation:
    Solve for b by simplifying both sides of the equation, then isolating the variable.
    1) Subtract 3/4b from both sides.
    6+ 2/3b− 3/4b = -4
    2) Combine 2/3b and -3/4b to get -1/12b
    3) Subtract 6 from both sides
    6-6-1/12b
    4) subtract 6 from -4 to get -10
    -1/12b = -10
    5) multiply both sides by -12 (the reciprocal of -1/12)
    b= -10(-12)
    6) multiply -10(-12) to get 120
    b=120

    Reply
  2. Answer:
    b=120
    Step-by-step explanation:
    Solve for b by simplifying both sides of the equation, then isolating the variable.
    1) Subtract 3/4b from both sides.
    6+ 2/3b− 3/4b = -4
    2) Combine 2/3b and -3/4b to get -1/12b
    3) Subtract 6 from both sides
    6-6-1/12b
    4) subtract 6 from -4 to get -10
    -1/12b = -10
    5) multiply both sides by -12 (the reciprocal of -1/12)
    b= -10(-12)
    6) multiply -10(-12) to get 120
    b=120
    Step-by-step explanation:

    Reply

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