Question

6+2/3b=3/4b-4
smallest common multiple of 3 and 4 is 12
72+8b=9b-48?
_-72______-72_
8b=9b-120

What are my next steps and what are my mistakes?

1. nguyetanh
b=120
Step-by-step explanation:
Solve for b by simplifying both sides of the equation, then isolating the variable.
1) Subtract 3/4b from both sides.
6+ 2/3b− 3/4b = -4
2) Combine 2/3b and -3/4b to get -1/12b
3) Subtract 6 from both sides
6-6-1/12b
4) subtract 6 from -4 to get -10
-1/12b = -10
5) multiply both sides by -12 (the reciprocal of -1/12)
b= -10(-12)
6) multiply -10(-12) to get 120
b=120

b=120
Step-by-step explanation:
Solve for b by simplifying both sides of the equation, then isolating the variable.
1) Subtract 3/4b from both sides.
6+ 2/3b− 3/4b = -4
2) Combine 2/3b and -3/4b to get -1/12b
3) Subtract 6 from both sides
6-6-1/12b
4) subtract 6 from -4 to get -10
-1/12b = -10
5) multiply both sides by -12 (the reciprocal of -1/12)
b= -10(-12)
6) multiply -10(-12) to get 120
b=120
Step-by-step explanation: