Question

50 POINTS+brainliest but reposting again because my points were used last time: How do you graph a quadratic equation in vertex form when the equation is a perfect square? Use x² -4x+4 as an example
you will be reported if your answer is absurd

Answers

  1. Answer:
    If it is a perfect square, k=0 in the form y=a(x-h)^2+k.
    Step-by-step explanation:
    x^2-4x+4=(x-2)^2, meaning that the vertex is at the point (2,0).
    Hope this helped 🙂

    Reply
  2. Answer:
    If it is a perfect square, k=0 in the form
    y=a(x-h) ^2+k.
    Step-by-step explanation:
    x^2-4x+4=(×-2) ^2, meaning that the vertex
    is at the point (2,0).

    Reply

Leave a Comment