3. Growth of Cholera bacteria. Suppose that the cholera bacteria in a colony grows unchecked according to the Law of Exponential Change. The colony starts with 1 bacterium and doubles in number every half hour. a. How many bacteria will the colony contain at the end of 24 h
Question
Answer:
2.814 * 10^14
Step-by-step explanation:
For exponential growth:
A = A0*e^kt
A = final amount ; A0 = initial amount ; t = time
Since bacterium doubles ever half hour ;
In 1 hour number of bacterium will be 2² = 4
Hence
Final amount after 1 hour
4 = 1*e^k*1
4 =e^k
Take In of both sides
In(4) = k
Number of bacterium in 24 hours
A = 1*e^In4 * 24
A = e^24In4
A = e^33.271064
A = 281474976710656
A = 2.814 * 10^14