(-3, 1)

-5-4-3

(-2,-4)

k

4

4

ob

1

2-

3+

(2/2)

What is the equation, in point-slope form, of the line

that is parallel to the given line and passes through the

point (-3, 1)?

Oy-1= -2(x+3)

Oy-1=-(x+3)

Oy – 1 =

Oy-1 =

(x+3)

(x+3)

-5-4-3

(-2,-4)

k

4

4

ob

1

2-

3+

(2/2)

What is the equation, in point-slope form, of the line

that is parallel to the given line and passes through the

point (-3, 1)?

Oy-1= -2(x+3)

Oy-1=-(x+3)

Oy – 1 =

Oy-1 =

(x+3)

(x+3)

Answer:Step-by-step explanation: