Y – 3 = X + 2 …………………. (1)
2X – 1 = Y ……………………… (2)

From (2),
2X – 1 = Y

Y = 2X – 1

Sub (2) into (1),
(2X-1) – 3 = X + 2

2X – 1 – 3 = X + 2

2X – X = 2 + 1 + 3

X = 6

Sub x=6 into (1),
Y = 2(6) – 1

Y = 12 – 1

Y = 11