2. Which equation describes a line that has

a slope of (4/5) and a y-intercept of (2/5)?

A) 5y + 4x = 2

C) Sy – 4x = 2

B) 4x5y = 2

D) -5y – 4x = 2

a slope of (4/5) and a y-intercept of (2/5)?

A) 5y + 4x = 2

C) Sy – 4x = 2

B) 4x5y = 2

D) -5y – 4x = 2

Answer:c,5y-4x=2

Step-by-step explanation:y=mx+b

y=4/5x+2/5

so m=4/5, and y intercept x=0 so y=2/5

Answer:C

Step-by-step explanation:The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = [tex]\frac{4}{5}[/tex] and c = [tex]\frac{2}{5}[/tex] , then

y = [tex]\frac{4}{5}[/tex] x + [tex]\frac{2}{5}[/tex] ( multiply through by 5 to clear the fractions )

5y = 4x + 2 ( subtract 4x from both sides )

5y – 4x = 2 → C