2. Which equation describes a line that has
a slope of (4/5) and a y-intercept of (2/5)?
A) 5y + 4x = 2
C) Sy – 4x = 2
B) 4x5y = 2
D) -5y – 4x = 2
Question
Question
2. Which equation describes a line that has
a slope of (4/5) and a y-intercept of (2/5)?
A) 5y + 4x = 2
C) Sy – 4x = 2
B) 4x5y = 2
D) -5y – 4x = 2
Answer:
c,5y-4x=2
Step-by-step explanation:
y=mx+b
y=4/5x+2/5
so m=4/5, and y intercept x=0 so y=2/5
Answer:
C
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = [tex]\frac{4}{5}[/tex] and c = [tex]\frac{2}{5}[/tex] , then
y = [tex]\frac{4}{5}[/tex] x + [tex]\frac{2}{5}[/tex] ( multiply through by 5 to clear the fractions )
5y = 4x + 2 ( subtract 4x from both sides )
5y – 4x = 2 → C