11. a bag contains 8 red marbles, 9 yellow marbles, and 7 green marbles. how many additional red marbles must be added

Question

11. a bag contains 8 red marbles, 9 yellow marbles, and
7 green marbles. how many additional red marbles
must be added to the 24 marbles already in the bag so
that the probability of randomly drawing a red marble
is
15.
a 11
b. 16
c. 20
d. 24
e. 32

sori · Answer

To get a  probability  of 3/5,  16 red marbles  must be added.       How many additional red marbles must be added?   There are 8 red, 9 yellow, and 7 green marbles, for a total of:  8 + 9 + 7 = 24.    The  probability  of getting a particular color of marble is given by the quotient between the number of marbles of that color and the total number of marbles.    Here, we want to get a  probability  of drawing a red marble equal to 3/5.  So, if we add x red marbles, the  probability  of getting a red marble will be:  P = (8 + x)/(24 + x)    And that must be equal ot 1/5, then we write:  (3/5) = (8 + x)/(24 + x)    If we multiply both sides bt (24 + x), we will get:  3*(24 + x)/5 = 8 + x    Now we can solve that for x.  3*24/5 - 8 = x - x(3/5) = (2/5)*x    x = (3*24/5)*(5/2) - (5/2)*8 = 16    So  16 red marbles  must be added, the correct option is b.    If you want to learn more about  probability , you can read:  https://brainly.com/question/251701  #SPJ1

How many additional red marbles must be added?

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