1/(x-2)+1/(x+3)=1/5 solve the problem for me​

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   Final value : x² -9x – 11

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   Step by step

   [tex] \frac{1}{(x – 2)} + \frac{1}{(x + 3)} = \frac{1}{5} [/tex]

   [tex] \frac{(x + 3) + (x – 2)}{(x – 2)(x + 3)} = \frac{1}{5} [/tex]

   [tex] \frac{2x + 1}{ {x}^{2} + 3x – 2x – 6 } = \frac{1}{5} [/tex]

   [tex] \frac{2x + 1}{ {x}^{2} + x – 6} = \frac{1}{5} [/tex]

   2x + 1 = ⅕ × (x² + x – 6)

   2x + 1 = ⅕x² + ⅕x – 6/5

   1/5x² +1/5x – 2x – 6/5 – 1 = 0

   1/5x² -9/5x – 11/5 = 0

   x² – 9x – 11 = 0. #times by 5

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   #Give me brainliest pls im tired typing all of this

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